We have to find the radius of the circle inscribed in a
triangle with sides of length 13, 14 and 15.
Now we have
the area of a triangle given as sqrt [ s ( s-a) (s-b) (s-c)] and it is also equal to r*s
where s is the semi perimeter and r is the radius of the inscribed
circle.
So r*s = sqrt [ s ( s-a) (s-b)
(s-c)]
r = sqrt [ s ( s-a) (s-b) (s-c)] / s = sqrt [( s-a)
(s-b) (s-c)]/ s ].
As the sides are 13, 14 and 15, the semi
perimeter s = 21 .
So substituting we get r = sqrt [ 8* 7*
6 / 21] = sqrt 16 = 4.
So the required radius
is 4
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