What are the new freezing and boiling points of water if 50 g of ethylene glycol(molecular mass = 62 g/mol) is added to 50 g of water?

When an impurity is dissolved in water the temperature at which
water freezes drops and the temperature at which it boils rises. The change in the freezing point
is given by dTf = Kf*cm and the change in the temperature at which it boils is given by dTb =
Kb*cm, where Kf and Kb are constants for a liquid and cm is the the molality of the
impurity.

Here, we have 50 g of ethylene glycol with a molecular
mass of 62 g/mole. 50 g is 0.8065 mole. When this is dissolved in 50 g of water we get a molality
of 0.8065/0.05 = 16.13

The constant Kf for water is 1.858 and Kb is
0.521.

The change in boiling point is 8.40 degrees Celsius or the
new boiling temperature is 108.4 degrees Celsius.

The change in the
freezing point is 29.96 degrees Celsius or the new freezing point is -29.96 degrees
Celsius.