What is the weight of the empty box in the following case:A box contains an unknown number of apples. The total weight of the box and the apples is...

Let us denote the weight of the box by B and the weight of
the apples by A. Now initially we have A + B = 200, After 3/4 of the apples have been
removed, we have the weight of the box and the apples as 64. This can be written as B +
A / 4 = 64.

Now from the first equation A + B = 200, write
A in terms of B as A = 200 – B.

Substitute this in B + A/4
= 64

=> B + (200 – B)/4 =
64

=> B + 200 / 4 – B/4 =
64

=> 3B/4 = 64 –
50

=> 3B/4 =
14

=> B =
(14*4)/3

=> B = 56/
3

Therefore the empty box weighs 56/3
kg.