If f(x) = (√x)/3 , then f ^-1 (x) =Please help me im stuck and have no idea how to solve it. Thanks.

 f(x) = (√x)/3 , then f ^-1 (x)
=

We have the function f(x) = sqrtx/
3

We need to find the inverse f^-1
(x)

==>let y = sqrtx / 3

Let us
multiply by 3:

==> 3y =
sqrtx

Now we will square both
sides:

==> (3y)^2 = x

==>
x= 9y^2

Now we will rewrite x and y and y as
x:

==> y = 9x^2

Then, the
inverse of the function f(x) is:

f^-1 (x) = 9x^2