Find the height of the cylinder, to the nearest tenth, if the volume is 231 and the circumference of the base is 8pi

Given that the volume of a cylinder is
231.

Then we know that:

v = r^2 * pi *
h such that r is the radius and h is the height.

But we are given
that the circumference of the base is 8pi.

==> C = 2* pi *r =
8pi

=> r = 8pi/2pi = 4

Then the
radius of the base is 4 .

Now we will substitute the volume and
radius into the equations.

==> v= r^2 * pi *
h

==> 231 = 4^2 * pi *
h

==> h = 231/ 16pi =
4.6

Then the height , to the nearest tenth, is 4.6
units.