Given the inequality 3=< 2b-3 =<
13.
We need to find all possible b values where the
inequality holds.
Let us solve the same way we solve the
equality.
==> 3 =< 2b-3 =<
13
The goal is to isolate b by itself in the middle of the
inequality.
==> We will add 3 to all
sides.
==> 3+ 3 =< 2b -3 + 3 =< 13 +
3
==> 6 =< 2b =<
16.
Now we will divide all terms by
2.
==> 6/2 =< 2b/2 =<
16/2
==> 3 =< b ==<
8.
Then we notice that b values are bounded by the numbers
3 and 8.
Then, b belongs to the interval [ 3,
8].
==> b = [ 3,
8].
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