Please solve the equation: (2x+1)(3x-2)=55

(2x+ 1)(3x-2) = 55

We need to
find x values that satisfies the equation.

First, let us
expand the brackets.

==> 2x*3x + 1*3x + 2x*-2 + 1*-2
= 55

==> 6x^2 +3x - 4x - 2 =
55

Now we will subtract 55 from both
sides.

==> 6x^2 - x -2 - 55 =
0

==> 6x^2 - x - 57 =
0.

Now we can factor or use the formula to determine the
roots of the quadratic equation.

Let us
factor.

==> (6x-19) ( x +3) =
0

==> (6x-19) = 0 ==> 6x = 19 ==> x =
19/6

==> (x+3) = 0 ==> x =
-3.

Then, there are two possible
solutions.

x = { -3,
19/6}