Given f = 3x - m find m if the point (-1,-5) is on the line. For m = 2 find the point that is on the line and it has similar coordinates.

If the given point (-1,-5) belongs to the line y= 3x - m,
then:

f(-1) = -5

f(-1) =
3*(-1) - m

f(-1) = -3 - m

-3 -
m = -5

m = 5 - 3

m =
2

The equation of the line
is:

y = 3x - 2

We'll note the
point that has like coordinates and it belongs to the line y = 3x - 2 as
M(n,n).

Since the point is located on the line y = 3x - 2,
it's coordinates verify the expression of the line.

We'll
put y = f(x) and we'll substitute x and y by the coordinates of the given
point:

f(n) = 3n-2 (1)

But
f(n) = n (2)

We'll conclude from (1) and (2)
that:

3n-2 = n

We'll isolate n
to the left side. For this reason, we'll subtract n both
sides:

3n - n = 2

2n =
2

n = 1

The
point located on the line y = 3x - 2 has the coordinates
(1;1).