5 - 3 l 2C+5 l < 13
To solve
for C, first we need to isolate the absolute value on the left
side.
First, we wiil subtract 5 from both
sides.
==> -3 l2C + 5 l < 13 -
5.
==> -3 l 2C + 5 l <
8
Now we will divide by -3.
( Notice
that when dividing or multiplyin by a negative number, we need to reverse the
inequality).
==> l 2C + 5 l >
-8/3
Now we have two cases:
(
Case(1):
2C + 5 > - 8/
3
==> 2C > -8/3 -
5
==> 2C > -23/3
Now we
will divide by 2:
==> C >
-23/6
Then, C = ( -23/6, inf).
Case(2):
- (
2C + 5) > -8/3
==> -2C - 5 >
-8/3
==> -2C > -8/3 +
5
==> -2C > 7/3
Divide
by -2 and reverse :
==> C <
-7/6
Then, C = ( - inf , -7/6)
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