The domain of definition of the given function contains
the admissible values of x for the logarithmic function to
exist.
We'll impose the constraint for the logarithmic
function to exist: the argument of logarithmic function has to be
positive.
x^2 - 5x + 6 >
0
We'll compute the roots of the
expression:
x^2 - 5x + 6 =
0
We'll apply the quadratic
formula:
x1 = [5 +/- sqrt(25 -
24)]/2
x1 = (5+1)/2
x1 =
3
x2 = 2
The expression is
positive over the intervals:
(-infinite , 2) U (3 ,
+infinite)
So, the logarithmic function is
defined for values of x that belong to the intervals (-infinite , 2) U (3 ,
+infinite).
The reunion of
intervals represents the domain of definition of the given function f(x) = log 2 (x^2 -
5x + 6).
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