AB = 13, BC = 15 , Ac =
13.
So we use heron's formula to find the A area of ABC.
Then
A rea = (1/2)BC* h, where h is the altitude of the
triangle.
So h = 2*Area /BC =
2Area/15...........(1)
Heron's formula for area Area of
triangle = sqrt{s(s-a)(s-b)(s-c)}
Where s = (a+b+c)/2 =
(15+14+13)/2 = 42/2 = 21
Area =
sqrt{21(21-15)(21-14)(21-13)} = sqrt {21*6*7*8} = 84.
Use
this area 84 in (1) to obtain h:
h = 2*84/15 =
11.2
Therefore the altitude from the side BC = 11.2
units.
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