Wednesday, March 12, 2014

Differentiate. g(x) = (x^2*cosx - cosx)

Given the function g(x) = (x^2*cosx -
cosx).


We need to differentiate the function
g(x).


First we will simplify the
function.


==> g(x) = x^2*cosx -
cosx


We notice that cosx is a common factor for both
terms.


Then we will factor
cosx.


==> g(x) = cosx( x^2 -
1)


Now we will use the product rule to find the
derivative.


Let g(x) = u*v such
that:


u= cosx  ==>   u' =
-sinx


v= x^2 -1  ==> v' =
2x


==> g'(x) = u'*v +
u*v'


                = -sinx(x^2-1) +
cosx*2x


                = 2x*cosx - x^2*sinx +
sinx


==> g'(x) = 2x*cosx - x^2*sinx +
sinx.

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