Given the polynomial f=4x^3-12x^2+mx+n find m, n if f(x)=0
for x=i.
If f(i) = 0, then i is the root of
4x^3-12x^2+mx+n.
Since complex roots appear in pairs , if i
is a root then -i os also a root..
Therefore f(x) the
factors, (x+i)(x-i) = x^2+1.
Therefore we can write
4x^3-12x^2+mx+n =
(x^2+1)(ax+b).
4x^3-12x^2+mx+n = ax^3+bx^2+ax+b.
We
equate the coefficients of like terms:
a = 4, b=
=-12,
m = a = 4
n = b =
-12.
Therefore m = 4 and n =
-12.
Therefore
4x^3-12x^2+mx+n = x^3-12x^2+4x-12.
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