In the domain of definition of the given function there
are found all the admissible values of x for the logarithmic function to
exist.
We'll impose the conditions for the logarithmic
function to exist: the argument of logarithmic function has to be
positive.
x^2 - 3x + 2 >
0
We'll compute the roots of the
expression:
x^2 - 3x + 2 =
0
We'll apply the quadratic
formula:
x1 = [3 +sqrt(9 -
8)]/2
x1 = (3+1)/2
x1 =
2
x2 = 1
The expression is
positive over the intervals:
(-infinite , 1) U (2 ,
+infinite)
So, the logarithmic
function exists for values of x that belong to the ranges (-infinite , 1) U (2 ,
+infinite).
The reunion of intervals
represents the domain of definition of the given function f(x) = ln (x^2 - 3x
+ 2).
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