Sunday, November 24, 2013

What is the domain of the function y=ln(x^2-3x+2) ?

In the domain of definition of the given function there
are found all the admissible values of x for the logarithmic function to
exist.


We'll impose the conditions for the logarithmic
function to exist: the argument of logarithmic function has to be
positive.


x^2 - 3x + 2 >
0


We'll compute the roots of the
expression:


x^2 - 3x + 2 =
0


We'll apply the quadratic
formula:


x1 = [3 +sqrt(9 -
8)]/2


x1 = (3+1)/2


x1 =
2


x2 = 1


The expression is
positive over the intervals:


(-infinite , 1) U (2 ,
+infinite)


So, the logarithmic
function exists for values of x that belong to the ranges (-infinite , 1) U (2 ,
+infinite).


The reunion of intervals
represents the domain of definition of the given function  f(x) = ln (x^2 - 3x
+ 2).

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