What is the sum of z1+z2=? z1=i/(1+i) z2=i/(1-i)

We have to determine the result of the sum of 2
ratios.

To calculate the sum of 2 ratios that do not have a
common denominator we'll have to calculate the LCD(least common denominator) of the 2
ratios.

We notice that LCD =
(1+i)(1-i)

We notice also that the product (1+i)(1-i) is
like:

(a-b)(a+b) = a^2 -
b^2

We'll write instead of product the difference of
squares, where a = 1 and b = i.

LCD =
(1+i)(1-i)

LCD = 1^2 -
i^2

We'll write instead of i^2 =
-1

LCD = 1 - (-1)

LCD =
2

Now, we'll multiply the first ratio by (1-i) and the
second ratio by (1+i):

 i(1-i)/2 + i(1+i)/
2

We'll remove the
brackets:

(i - i^2 + i +
i^2)/2

We'll eliminate like
terms:

2i/2

We'll simplify and
we'll get:

z1 + z2
=  i(1-i)/2 + i(1+i)/
2

 i(1-i)/2 +
i(1+i)/ 2 =
i

The result is a complex
number, whose real part is 0 and imaginary part is
1