Wednesday, November 19, 2014

Solve the inequation 8> x^2 – 4 > 4?

4 < x^2 - 4 <
8


Add 4 to both
sides.


==> 8 < x^2 <
12


Now let us separate and solve each
side.


==> 8 < x^2    and  x^2 <
12


Let us solve 8 <
x^2


Take the square root of both
sides.


==> sqrt8 < x and  sqrt8 <
-x


==> 2sqrt2 < x   and 
-2sqrt2 > x


==>
x = ( 2sqrt2,inf) U ( -inf, -2sqrt2)


Now the
other side.


==> x^2 <
12


==> x < sqrt12   OR    -x
< sqrt12


==> x < 2sqrt3   OR    x
> -2sqrt3


==> x = ( 2sqrt3,
inf) U ( -inf, -2sqrt3) 

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