Hope it is the sum product of the
roots:
We know that if ax^2+bx +c = 0 , and the roots x1 and x2,
then
the sum of roots is x1+x2 = -b/a and the product of the roots
is x1x2 = c/a. We apply this to the given equations:
a.)
2x^2-8x+5=0'
Here identify a= 2, b = -8 and c =
5.
Sum x1+x1 = - (-8/2) = 4 and product of roots x1x2 = 5/2 =
2.5.
b.)3x^2-9x=0.
Here a =
3, b= -9. c = 0 ( c is absent.)
So sum of the roots x1+x2 =
-(-9/3) = 3
Product of the roots x1x2 = 0/3 =
0.
c.)-.5 (in fraction
form)x^2-3x+2=0
a = -0.5 . b = -3 and c =
-2.
Therefore sum of the roots = x1+x2 = -(-3/-0.5) =
-6/
Product of the roots = x1x2 = -2/-0.5 =
4.
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