In the scenario below, how long is the ski jumper airborne, and where does the ski jumper land on the incline?A ski jumper travels down a slope and...

While landing the the ski jumper  makes a  slope of of 33
degree with the horizotal.

The ski jumper has the initial
horizontal velocity of 25m/s. The horizontal velocity componet of the ski jumper is not
affected by the gravity at any time during the fall. But the vertical velocity of the
jumper increases every second by the acceleration due to
gravity.

Therefore at the time of fall the slope of the
trajectory must be (dy/dt )(dx/dt) = Vertical velocity / horizotal velocity =  tan 33
degree.

Therefore the vertical velocity v = Horizontal
velocity * tan33 deg = 25tan 33 deg .

v = 25tan
33.

Therefore the vertical velocity is gained from the
gravitional acceleration g in time t seconds .

Therefore t
= (25tan33)/g = (25tan33)/9.81 = 1.65 seconds.

Therefore
the ski jumper was airborn 1.65 seconds nearly.