We notice that substituting x by the value 1, we'll verify the
equation, so x = 1 is the solution of the equation.
2^1 = 5^1 -
3^1
2 = 5 - 3
Now, we'll have to
verify if x = 1 is the only solution for the given equation or if there are
more.
We'll divide the equation, both sides, by the greatest
exponential, namely 5^x:
(2/5)^x= 1 -
(3/5)^x
We'll put f(x) = 1 -
(3/5)^x
We'll calculate f(1):
2/5 = 1 -
3/5
2/5 = (5-3)/5
2/5 =
2/5
The exponential functions (2/5)^x and (3/5)^x are decreasing
functions (the denominator is bigger than numerator), so f(x) is a decreasing function,
too.
If f(x) is a decreasing function, it could have
only one solution x = 1.
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