To solve 3|x-2|+7 = 12.
|x-2|
is the positive of the expression (x-2).
So |x-2| = x-2
when x> 2. And |x-2| = 2-x , when x <
0.
Therefore when x > 2, the given equation
is:
3(x-2)+7 = 12.
3(x-2) =
12-7 = 5.
x-2 = 5/3.
x = 2+5/3
= 11/3.
When x < 2, the given equation could be
written as:
3(2-x)+7 = 12.
6
-3x +7 = 12
-3x+13 = 12.
-3x =
12-13 = -1.
x = -1/-3 =
1/3.
x= 1/3.
Therefore from
the cases , the solution we get : x= 11/3 or x= 1/3.
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