Given that the speed of the plane with the wind = 1500/3
hours.
==> The speed = 1500/3 = 500
mph.
Let (s) be the apeed of the plane in still
air.
Letthe speed of the wind be
(sw).
==> 500 = s +
sw...............(1)
Also, we are given that the speed
against the wind = 1500/(3 1/3).
==> 1500/ (10/3) =
1500*3/10 = 450 mph.
==> 450 = s -
sw..................(2)
Now we will add equation (1) and
(2);
==> 2s =
950
==> s = 950/2 =
475.
Then, the speed of the plane in still
air is 475 mph.
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