Determine the point on the x and y axes where 16x + y + 10 =0 intersects them.

We are given the line 16x + y + 10 =0. Now we need to find
the point in the x and y axes where this line intersects them. That is the x and the y
intercepts. we can write the line in the form
x/a+y/b=1

where a is the x intercept and b is the y
intercept.

16x + y + 10
=0

Mover the constant to the other
side

16x + y = -10

Divide all
the terms by -10

(16/-10) x + y/-10 =
1

=> x/ (-10/16) + y/ (-10)
=1

Therefore the x and the y intercepts are (-10/16,0) and
(0,-10).

So the line intersects the x axis at
(-10/16, 0) and the y axis at (0, -10)