1.Given the inequalities I. 3x-y-2 III.x-6y(_>)-28 (2,5) satisfies 2. can a graph be plotted for the inequality...

To verify if the point (2,5) is the solution of the system
of inequalities, we'll simply substitute x by 2 and y by 5 in each inequality, as it
follows:

3*2 - 5<5

6 -
5 < 5

1 < 5

So,
(2,5) verify the first inequality.

II. 2*2 - 3*5 >
-2 4 - 15 > -2 -11 > -2 As we can notice, -11 < -2, so the interval
(2,5) doesn't verify the second inequality. III. 2 - 6*5(_>)-28 2 - 30 = -28 -28
= -28 The interval  (2,5) verify the 3rd inequality.

To
plot the graph, we'll have to re-write the
inequality.

3x-4y-8 >=
0

We'll isolate -4y to the left side. For this reason,
we'll subtract 3x - 8 both sides:

-4y >= -3x +
8

We'll multiply by -1 and we'll change the direction of
the inequality:

4y =< 3x -
8

We'll divide by 4:

y
=< 3x/4 - 2

Now, we'll input values for x and we'll
find values for y.