If the sum of the first two of the five consecutive odd integers is 52, what is the sum of the last two integers?

Let the five odd integers be:

x ,
x+2 , x+4, x+6 , x+ 8

Then given the sum of the first two integers
is 52

==> x + (x+ 2) = 52

Let us
combine like terms:

x + x + 2 =
52

==> 2x + 2 = 52

==> 2x
= 50

==> x = 25

Then the first
number is 25

Then the second numbers is 25+2 =
27

The third consecutive integer = 25+ 4 =
29

The fourth integer is  = 25+ 6) =
31

The fifth integer is = 25+8 =
33

Then the sum of the last two integers
is:

 31 + 33 =
64