Determine the slope of the line 8x - 32y -9 = 0?

We have to find the slope of the line 8x – 32y -9
=0.

First we express the equation in the form y = mx+c,
where m is the slope of the line and c is the
y-intercept.

8x – 32y -9
=0

keep y on one side and move x and the constant to the
other side

=> -32y =
9-8x

divide both the sides by
-32

=> y = (9/-32) + (8/32)
x

simplify all the
factors

=> y = -9/32
+x/4

Therefore we get that m = 1/4 for the given
equation.

The required slope is
1/4.