We'll suggest another method of getting the inverse
   function.
We know that the product of derivative and it's inverse is
   1.
f'(x)*[f^-1(x)]' =1
We'll divide
   both sides by f'(x):
[f^-1(x)]' =
   1/f'(x)
We'll calculate the integral of functions both
   sides:
Int [f^-1(x)]'dx = Int
   dx/f'(x)
We'll differentiate the function
   f(x):
f'(x) = [(e^3x)*14 - 21]'
f'(x) =
   42*e^3x
f^-1(x) = Int dx/42*e^3x
Int
   dx/42*e^3x = (1/42)*Int e^-3xdx
Int dx/42*e^3x =
   -e^-3x/3*42
Int dx/42*e^3x =
   -1/126*e^3x
Therefore, the inverse function is:
   f^-1(x) = -1/126*e^3x.
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