What are the length, slope and the midpoint of PQ for P(7,11) and Q(-2,4)?

P(7,11), Q(-2,4)

(1) To find the
length :

The distance betwen two ponits (x1,y1) and (x2,y2) is given
by:

d = sqrt{(x2-x1)^2 +(y2-y1)^2} .

So
the distance PQ = sqrt{(-2-7)^2+(4-11)^2} = sqrt{(-9)^2 +(-7)^2} = sqrt{81+49} =
sqrt130.

2) The slope m of the line joining the two points
(x1,y1)and(x2,y2) is given by:

 m = (y2-y1)/(x2-x1)
.

Therefore  slope of the line joining the line (7,11) and (-2,4)
is  given by: m = (4-11)/(-2-7) = -7/-9 = 7/9. So the slope is m =
7/9.

3)

The mid point of the two points
(x1,y1) and (x2, y2)  is  ((x1+x2)/2 , (y1+y2)/2).

Therefore the mid
point of  (7,11) and (-2,4) is ((7-2)/2 , (11+4)/2) = ( 5/2 , 15/2).