What is the equation of the line with x and y intercepts 4 and 7 respectively.

The equation of the line with x and y in the standard double
intercept form is x/a+y/b = a. Where  intercept is a, and y intercept is
b.

Therefore the equation of the line  with x intercept 4 and y
interceppt 7 is x/4 +y/7 = 1.

We check whether this is
true:

x intercept is got by putting y= 0 in x/4+y/7 =
1:

 So x/4 + 0/7 = 1,, So x/4 = 1, or x=
4.

We check whether y intercept is 7: We get y intercept by putting
x = 0 in x/4+y/7 = 1. So,  0/4+y/7 = 1, or y/7 = 1. So y =
7.

Therefore x/4+y/7 = 1 is the required equation. We write the
equation  in  ax+by+c = 0 form by mutiplying  x/4+y/7 = 1 by 4*7 = 28
:

28(x/4+y/7) = 1*28. This gives us the equation,7x +4y = 28. Or
7x+4y-28 = 0.