The mid point of AB is (3,-4) and B
   (1,6).
Therefore we use mid point formula M(x,y) = ((Ax+Bx)/2,
   Ay+By)/2)
Therefore (3, -4) = (( Ax  +1)/2 , (Ay
   +6)/2)
We  equate x coordinates and y coordinates separately and
   solve for Ax and Ay:
3 = (Ax+1)/2.
6 =
   Ax+1. So Ax = 6-1 = 5.
-4 = (Ay +
   6)/2.
-8 = Ay +6.  So Ay = -8 -6 =
   -14.
Therefore the  coordinates of A  = ( 5,
   -14).
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