The mid point of AB is (3,-4) and B
(1,6).
Therefore we use mid point formula M(x,y) = ((Ax+Bx)/2,
Ay+By)/2)
Therefore (3, -4) = (( Ax +1)/2 , (Ay
+6)/2)
We equate x coordinates and y coordinates separately and
solve for Ax and Ay:
3 = (Ax+1)/2.
6 =
Ax+1. So Ax = 6-1 = 5.
-4 = (Ay +
6)/2.
-8 = Ay +6. So Ay = -8 -6 =
-14.
Therefore the coordinates of A = ( 5,
-14).
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